What is the derivative of x^2+2x-8 ?

The derivative of x^2+2x-8 is 2x+2

What is the first derivative of x^2+2x-8 ?

The first derivative of x^2+2x-8 is 2x+2

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\frac{d}{d x} (x^{2} + 2 x - 8)

2 x + 2

Solution steps

\frac{d}{d x} (x^{2} + 2 x - 8)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (x^{2}) + \frac{d}{d x} (2 x) - \frac{d}{d x} (8)

\frac{d}{d x} (x^{2}) = 2 x

\frac{d}{d x} (2 x) = 2

\frac{d}{d x} (8) = 0

= 2 x + 2 - 0

Simplify

= 2 x + 2

\frac{\partial}{\partial x} (e^{- x} tan (y))

e^{- 2 t} sin (3 π t)

\frac{d y}{d x} + 2 y = 50

\frac{d}{d t} (6 sin^{3} (t))

\frac{d ^{2}}{d x ^{2}} (\frac{5}{6 t ^{4}})

What is the derivative of x^2+2x-8 ?
The derivative of x^2+2x-8 is 2x+2
What is the first derivative of x^2+2x-8 ?
The first derivative of x^2+2x-8 is 2x+2