What is the limit as h approaches 0 of (3e^h-3)/h ?

The limit as h approaches 0 of (3e^h-3)/h is 3

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

limit as h approaches 0 of (3e^h-3)/h

h \to 0 lim (\frac{3 e ^{h} - 3}{h})

3

Solution steps

h \to 0 lim (\frac{3 e ^{h} - 3}{h})

Apply L'Hopital's Rule

: h \to 0 lim (\frac{3 e ^{h}}{1})

= h \to 0 lim (\frac{3 e ^{h}}{1})

Plug in the value

h = 0

= \frac{3 e ^{0}}{1}

Simplify

= 3

\int_{- \infty}^{0} \frac{x}{x ^{4} + 4} d x

\int \frac{2}{4 x ^{2} + 4} d x

\int_{l n (3)}^{l n (5)} e^{2 x} d x

f (x) = 3^{x}, at x = 0

\int - 9 sin (3 t) d t

What is the limit as h approaches 0 of (3e^h-3)/h ?
The limit as h approaches 0 of (3e^h-3)/h is 3