derivative of (x^2-9x+7/(x^2+9))

Lösung

\frac{d}{d x} (\frac{x ^{2} - 9 x + 7}{x ^{2} + 9})

\frac{9 x ^{2} + 4 x - 81}{( x ^{2} + 9 ) ^{2}}

Schritte zur Lösung

\frac{d}{d x} (\frac{x ^{2} - 9 x + 7}{x ^{2} + 9})

Wende die Quotientenregel an:

(\frac{f}{g})^{'} = \frac{f ^{'} \cdot g - g ^{'} \cdot f}{g ^{2}}

= \frac{\frac{d}{d x} ( x ^{2} - 9 x + 7 ) ( x ^{2} + 9 ) - \frac{d}{d x} ( x ^{2} + 9 ) ( x ^{2} - 9 x + 7 )}{( x ^{2} + 9 ) ^{2}}

\frac{d}{d x} (x^{2} - 9 x + 7) = 2 x - 9

\frac{d}{d x} (x^{2} + 9) = 2 x

= \frac{( 2 x - 9 ) ( x ^{2} + 9 ) - 2 x ( x ^{2} - 9 x + 7 )}{( x ^{2} + 9 ) ^{2}}

Multipliziere aus

(2 x - 9) (x^{2} + 9) - 2 x (x^{2} - 9 x + 7) : 9 x^{2} + 4 x - 81

= \frac{9 x ^{2} + 4 x - 81}{( x ^{2} + 9 ) ^{2}}

d er i v a t i v e 10 tan^{2} (6 x)

\frac{d}{d x} (2 sin (2 x) - 4 sin^{9} (2 x))

\frac{d}{d x} (x^{\frac{2}{3}} (5 - x))

a re a 19 - x^{2}, - 2 x + 16, - 5, - 19

\frac{\partial}{\partial x} (y \cdot ∣ x ∣)