What is integral from 0 to 9 of f(x) ?

The answer to integral from 0 to 9 of f(x) is (81f)/2

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

integral from 0 to 9 of f(x)

\int_{0}^{9} f (x) d x

\frac{81 f}{2}

Solution steps

\int_{0}^{9} f x d x

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= f \cdot \int_{0}^{9} x d x

Apply the Power Rule

: [\frac{x ^{2}}{2}]_{0}^{9}

= f [\frac{x ^{2}}{2}]_{0}^{9}

Compute the boundaries:

\frac{81}{2}

= f \frac{81}{2}

Simplify

= \frac{81 f}{2}

x (\frac{d y}{d x}) - (1 + x) y = x y^{2}

3 e^{7}

\frac{d}{d x} (\frac{1 - 5 x}{1 + 5 x})

\frac{\partial}{\partial y} (- 2 y e^{x^{2} - y^{2}})

\int (1 + \frac{9 x}{8}) d x

What is integral from 0 to 9 of f(x) ?
The answer to integral from 0 to 9 of f(x) is (81f)/2