integral from-1 to 1 of 2^x

Lösung

\int_{- 1}^{1} 2^{x} d x

\frac{3}{2 ln ( 2 )}

Dezimale

2.16404 \dots

Schritte zur Lösung

\int_{- 1}^{1} 2^{x} d x

\int a^{x} d x = \frac{a ^{x}}{ln a}

= [\frac{2 ^{x}}{ln ( 2 )}]_{- 1}^{1}

Berechne die Grenzen:

\frac{3}{2 ln ( 2 )}

= \frac{3}{2 ln ( 2 )}

\frac{d}{d x} (2 + \frac{3}{1 + ( x + 1 ) ^{2}})

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