integral from 0 to 7 of sqrt(1+x)

Lösung

\int_{0}^{7} 1 + x d x

\frac{32 2 - 2}{3}

Dezimale

14.41827 \dots

Schritte zur Lösung

\int_{0}^{7} 1 + x d x

Wende U-Substitution an

= \int_{1}^{8} u d u

Wende die Potenzregel an

= [\frac{2}{3} u^{\frac{3}{2}}]_{1}^{8}

Berechne die Grenzen:

\frac{32 2}{3} - \frac{2}{3}

= \frac{32 2}{3} - \frac{2}{3}

Vereinfache

= \frac{32 2 - 2}{3}

d er i v a t i v e f (x) = 4 x sin (x)

\int cos^{2} (2 x) 2 d x

x \to 0 - lim (\frac{5}{x} - \frac{5}{x})

d er i v a t i v e sin (2 x + 1)

\frac{d}{d x} (\frac{3 x}{2 x + 3})