laplacetransform 2*sin(3t)

Lösung

laplace transformation

2 \cdot sin (3 t)

\frac{6}{s ^{2} + 9}

Schritte zur Lösung

L {2 sin (3 t)}

Verwende die konstante Multiplikationseigenschaft der Laplace-Transformation:

For function

f (t)

and constant

a : L {a \cdot f (t)} = a \cdot L {f (t)}

= 2 L {sin (3 t)}

L {sin (3 t)} : \frac{3}{s ^{2} + 9}

= 2 \cdot \frac{3}{s ^{2} + 9}

Fasse

2 \frac{3}{s ^{2} + 9}

zusammen:

\frac{6}{s ^{2} + 9}

= \frac{6}{s ^{2} + 9}

a re a y = e^{3 x}, y = e^{- 3 x}, x = - 1

\int_{0}^{2} - 6 x^{3} x^{2} + 4 d x

\frac{d}{d x} (1 + x + 5 x^{2})

\int_{- 2}^{1} 2 - x^{2} - x d x

d er i v a t i v e (x^{9} - 1)^{3}