What is the integral of ((x^2-1))/(sqrt(x)) ?

The integral of ((x^2-1))/(sqrt(x)) is 2/5 x^{5/2}-2sqrt(x)+C

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integral of ((x^2-1))/(sqrt(x))

\int \frac{( x ^{2} - 1 )}{x} d x

\frac{2}{5} x^{\frac{5}{2}} - 2 x + C

Solution steps

\int \frac{x ^{2} - 1}{x} d x

Expand

\frac{x ^{2} - 1}{x} : x^{\frac{3}{2}} - \frac{1}{x}

= \int x^{\frac{3}{2}} - \frac{1}{x} d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int x^{\frac{3}{2}} d x - \int \frac{1}{x} d x

\int x^{\frac{3}{2}} d x = \frac{2}{5} x^{\frac{5}{2}}

\int \frac{1}{x} d x = 2 x

= \frac{2}{5} x^{\frac{5}{2}} - 2 x

Add a constant to the solution

= \frac{2}{5} x^{\frac{5}{2}} - 2 x + C

\int 2 x 2 x - 3 d x

n = 1 \sum \infty \frac{7}{n ( n + 3 )}

e^{x} x - 4 e^{x}

x \to 0 lim (\frac{6 ^{x} - 1 0 ^{x}}{x})

\frac{d}{d x} (arccsc (4 x))

What is the integral of ((x^2-1))/(sqrt(x)) ?
The integral of ((x^2-1))/(sqrt(x)) is 2/5 x^{5/2}-2sqrt(x)+C