What is the d/(dt)(7cos^3(t)) ?

The d/(dt)(7cos^3(t)) is -21cos^2(t)sin(t)

What is the first d/(dt)(7cos^3(t)) ?

The first d/(dt)(7cos^3(t)) is -21cos^2(t)sin(t)

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\frac{d}{d t} (7 cos^{3} (t))

- 21 cos^{2} (t) sin (t)

Solution steps

\frac{d}{d t} (7 cos^{3} (t))

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= 7 \frac{d}{d t} (cos^{3} (t))

Apply the chain rule:

3 (cos (t))^{2} \frac{d}{d t} (cos (t))

= 3 (cos (t))^{2} \frac{d}{d t} (cos (t))

\frac{d}{d t} (cos (t)) = - sin (t)

= 7 \cdot 3 (cos (t))^{2} (- sin (t))

Simplify

= - 21 cos^{2} (t) sin (t)

\int (4 cos^{2} (x)) d x

d er i v a t i v e e^{e^{- x}}

\int cos (3 π t) d t

\int 1 - \frac{3}{y} d y

f (x) = - 8 sin (x)

What is the d/(dt)(7cos^3(t)) ?
The d/(dt)(7cos^3(t)) is -21cos^2(t)sin(t)
What is the first d/(dt)(7cos^3(t)) ?
The first d/(dt)(7cos^3(t)) is -21cos^2(t)sin(t)