What is the integral of (2^x+e^pi) ?

The integral of (2^x+e^pi) is (2^x)/(ln(2))+e^pix+C

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integral of (2^x+e^pi)

\int (2^{x} + e^{π}) d x

\frac{2 ^{x}}{ln ( 2 )} + e^{π} x + C

Solution steps

\int 2^{x} + e^{π} d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int 2^{x} d x + \int e^{π} d x

\int 2^{x} d x = \frac{2 ^{x}}{ln ( 2 )}

\int e^{π} d x = e^{π} x

= \frac{2 ^{x}}{ln ( 2 )} + e^{π} x

Add a constant to the solution

= \frac{2 ^{x}}{ln ( 2 )} + e^{π} x + C

e^{7}

d x + e^{3} x d y = 0

f (x) = x^{2}, (- 1, - 3)

x^{2} - 4 x, x

x \to 3 lim (5 (x - 3) ln (x - 3))

What is the integral of (2^x+e^pi) ?
The integral of (2^x+e^pi) is (2^x)/(ln(2))+e^pix+C