What is the tangent of y=7e^x+x,(0,7) ?

The tangent of y=7e^x+x,(0,7) is y=8x+7

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tangent of y=7e^x+x,(0,7)

tangent of

y = 7 e^{x} + x, (0, 7)

y = 8 x + 7

Solution steps

Find the slope of

y = 7 e^{x} + x : \frac{d y}{d x} = 7 e^{x} + 1

Compute the slope of

y = 7 e^{x} + x

(0, 7) : m = 8

Find the line with slope m=

8

and passing through

(0, 7) : y = 8 x + 7

y = 8 x + 7

4

\int_{0}^{6} x^{2} - 6 x d x

x^{2}, x + 5

y^{^{''}} - 6 y^{^{'}} + 8 y = 2 cos (3 t), y (0) = 2, y^{^{'}} (0) = - 4

e^{y} y^{^{'}} = e^{y} + 4 x