What is the tangent of f(x)=4x^2+7,(-3,43) ?

The tangent of f(x)=4x^2+7,(-3,43) is y=-24x-29

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tangent of f(x)=4x^2+7,(-3,43)

tangent of

f (x) = 4 x^{2} + 7, (- 3, 43)

y = - 24 x - 29

Solution steps

Find the slope of

f (x) = 4 x^{2} + 7 : \frac{df ( x )}{d x} = 8 x

Compute the slope of

f (x) = 4 x^{2} + 7

(- 3, 43) : m = - 24

Find the line with slope m=

- 24

and passing through

(- 3, 43) : y = - 24 x - 29

y = - 24 x - 29

(- 4, - 6), (4, - 2)

f (x) = \frac{- 4 x}{x ^{2} + 1}, (1, - 2)

\int \frac{x}{e ^{- 3 x}} d x

\int tan^{2} (w) d w

\frac{\partial}{\partial x} (- a e^{k z} w sin (k x - wt))

What is the tangent of f(x)=4x^2+7,(-3,43) ?
The tangent of f(x)=4x^2+7,(-3,43) is y=-24x-29