What is the derivative of x^{2/3}-1 ?

The derivative of x^{2/3}-1 is 2/(3x^{1/3)}

What is the first derivative of x^{2/3}-1 ?

The first derivative of x^{2/3}-1 is 2/(3x^{1/3)}

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\frac{d}{d x} (x^{\frac{2}{3}} - 1)

\frac{2}{3 x ^{\frac{1}{3}}}

Solution steps

\frac{d}{d x} (x^{\frac{2}{3}} - 1)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (x^{\frac{2}{3}}) - \frac{d}{d x} (1)

\frac{d}{d x} (x^{\frac{2}{3}}) = \frac{2}{3 x ^{\frac{1}{3}}}

\frac{d}{d x} (1) = 0

= \frac{2}{3 x ^{\frac{1}{3}}} - 0

Simplify

= \frac{2}{3 x ^{\frac{1}{3}}}

x, x^{1}, 0, 1

n \to \infty lim (\frac{n}{4})

x \to 0 + lim (x^{2} ln (3 x))

\int 10 tan (x) sec^{4} (x) d x

\frac{\partial}{\partial y} (e^{x z})

What is the derivative of x^{2/3}-1 ?
The derivative of x^{2/3}-1 is 2/(3x^{1/3)}
What is the first derivative of x^{2/3}-1 ?
The first derivative of x^{2/3}-1 is 2/(3x^{1/3)}