en

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

y^'=e^{9y-x}

Solution

y^{^{'}} = e^{9 y - x}

Solution

y = - \frac{ln ( 9 e ^{- x} - c _{1} )}{9}

Solution steps

y^{'} (x) = e^{9 y - x}

Solve separable ODE:

y = - \frac{ln ( 9 e ^{- x} - c _{1} )}{9}

y = - \frac{ln ( 9 e ^{- x} - c _{1} )}{9}

Popular Examples

tangent of f(x)=x^3,\at x=-5 tangent of

f (x) = x^{3}, at x = - 5

limit as x approaches 0 of 1-cos(3x)

x \to 0 lim (1 - cos (3 x))

limit as x approaches infinity of log_{2}(log_{2}(x)-1)

x \to \infty lim (lo g_{2} (lo g_{2} (x) - 1))

integral from 0 to pi/2 of sin^5(x)

\int_{0}^{\frac{π}{2}} sin^{5} (x) d x

integral from 0 to 2 of 8000te^{-0.6t}

\int_{0}^{2} 8000 t e^{- 0.6 t} d t

Frequently Asked Questions (FAQ)

What is the solution for y^'=e^{9y-x} ?
The solution for y^'=e^{9y-x} is y=-(ln(9e^{-x}-c_{1}))/9