What is the integral from pi/6 to pi/4 of cos(x) ?

The integral from pi/6 to pi/4 of cos(x) is 1/(sqrt(2))-1/2

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integral from pi/6 to pi/4 of cos(x)

\int_{\frac{π}{6}}^{\frac{π}{4}} cos (x) d x

\frac{1}{2} - \frac{1}{2}

Decimal Notation

0.20710 \dots

Solution steps

\int_{\frac{π}{6}}^{\frac{π}{4}} cos (x) d x

Use the common integral:

\int cos (x) d x = sin (x)

= [sin (x)]_{\frac{π}{6}}^{\frac{π}{4}}

Compute the boundaries:

\frac{1}{2} - \frac{1}{2}

= \frac{1}{2} - \frac{1}{2}

s (t) = 5^{t}

\frac{d}{d x} (- 3 tan (x))

\int_{7}^{8} (\frac{7}{x ^{2}} - 1) d x

\int (\frac{x ^{2} + 1}{x ^{2}}) d x

\frac{d}{d x} (\frac{( x - 4 )}{x})

What is the integral from pi/6 to pi/4 of cos(x) ?
The integral from pi/6 to pi/4 of cos(x) is 1/(sqrt(2))-1/2