What is the sum from n=0 to infinity of (1/2)^{2n} ?

The sum from n=0 to infinity of (1/2)^{2n} is converges

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sum from n=0 to infinity of (1/2)^{2n}

n = 0 \sum \infty (\frac{1}{2})^{2 n}

converges

Solution steps

n = 0 \sum \infty (\frac{1}{2})^{2 n}

Apply Series Ratio Test:

converges

= converges

y = \frac{1}{3} e^{3 x}

\int_{0}^{1} (2 x + 1)^{4} d x

f (x) = - 8 sin (x)

\int (z^{2}) d z

\frac{\partial}{\partial x} (\frac{1}{x} + \frac{1}{1 - x})

What is the sum from n=0 to infinity of (1/2)^{2n} ?
The sum from n=0 to infinity of (1/2)^{2n} is converges