What is the derivative of 3/((x-1)^2) ?

The derivative of 3/((x-1)^2) is -6/((x-1)^3)

What is the first derivative of 3/((x-1)^2) ?

The first derivative of 3/((x-1)^2) is -6/((x-1)^3)

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derivative of

\frac{3}{( x - 1 ) ^{2}}

- \frac{6}{( x - 1 ) ^{3}}

Solution steps

\frac{d}{d x} (\frac{3}{( x - 1 ) ^{2}})

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= 3 \frac{d}{d x} (\frac{1}{( x - 1 ) ^{2}})

Apply exponent rule:

\frac{1}{a} = a^{- 1}

= 3 \frac{d}{d x} ((x - 1)^{- 2})

Apply the chain rule:

- \frac{2}{( x - 1 ) ^{3}} \frac{d}{d x} (x - 1)

= - \frac{2}{( x - 1 ) ^{3}} \frac{d}{d x} (x - 1)

\frac{d}{d x} (x - 1) = 1

= 3 (- \frac{2}{( x - 1 ) ^{3}} \cdot 1)

Simplify

3 (- \frac{2}{( x - 1 ) ^{3}} \cdot 1) : - \frac{6}{( x - 1 ) ^{3}}

= - \frac{6}{( x - 1 ) ^{3}}

\frac{x ^{2}}{x + 2}

\frac{d}{d x} (A x^{2} + B x)

\int cos (5 x) sin (6 x) d x

\int x x + 3 d x

\frac{d y}{d x} = \frac{( x + 3 y )}{y - 3 x}

What is the derivative of 3/((x-1)^2) ?
The derivative of 3/((x-1)^2) is -6/((x-1)^3)
What is the first derivative of 3/((x-1)^2) ?
The first derivative of 3/((x-1)^2) is -6/((x-1)^3)