What is the tangent of f(x)= 1/(x^4),(-3, 1/81) ?

The tangent of f(x)= 1/(x^4),(-3, 1/81) is y= 4/243 x+5/81

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tangent of f(x)= 1/(x^4),(-3, 1/81)

tangent of

f (x) = \frac{1}{x ^{4}}, (- 3, \frac{1}{81})

y = \frac{4}{243} x + \frac{5}{81}

Solution steps

Find the slope of

f (x) = \frac{1}{x ^{4}} : \frac{df ( x )}{d x} = - \frac{4}{x ^{5}}

Compute the slope of

f (x) = \frac{1}{x ^{4}}

(- 3, \frac{1}{81}) : m = \frac{4}{243}

Find the line with slope m=

\frac{4}{243}

and passing through

(- 3, \frac{1}{81}) : y = \frac{4}{243} x + \frac{5}{81}

y = \frac{4}{243} x + \frac{5}{81}

\frac{1}{1 - x}, 12

\int \frac{2 x ^{3}}{x ^{2} - 4} d x

\frac{d}{d x} (∣ x - 3 ∣ - ∣ 2 x - 2 ∣ - 1 x e [- 2, 2])

\frac{d}{d x} (1 + x ln (x y - 5))

y^{^{'''}} + y^{^{'}} = 0

What is the tangent of f(x)= 1/(x^4),(-3, 1/81) ?
The tangent of f(x)= 1/(x^4),(-3, 1/81) is y= 4/243 x+5/81