What is area y=8x^4-8x^2,y=9x^2 ?

The answer to area y=8x^4-8x^2,y=9x^2 is (289sqrt(17))/(60sqrt(2))

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area y=8x^4-8x^2,y=9x^2

area

y = 8 x^{4} - 8 x^{2}, y = 9 x^{2}

\frac{289 17}{60 2}

Decimal Notation

14.04287 \dots

Solution steps

Apply the area formula:

\int_{- \frac{17}{2 2}}^{\frac{17}{2 2}} 8 x^{4} - 17 x^{2} d x

Solve

\int_{- \frac{17}{2 2}}^{\frac{17}{2 2}} 8 x^{4} - 17 x^{2} d x : \frac{289 17}{60 2}

The area is:

= \frac{289 17}{60 2}

3 (2 x cos (5 x) - 5 x^{2} sin (5 x))

(0.2) (5.4)

\frac{\partial}{\partial x} (u^{7} + v^{7})

\frac{d}{d x} ((1 + x)^{\frac{1}{x}})

\int_{0}^{\frac{π}{2}} cos^{9} (x) d x

What is area y=8x^4-8x^2,y=9x^2 ?
The answer to area y=8x^4-8x^2,y=9x^2 is (289sqrt(17))/(60sqrt(2))