integral from 0 to 9 of 1/3 x-2

解

\int_{0}^{9} \frac{1}{3} x - 2 d x

- \frac{9}{2}

十進法表記

- 4.5

解答ステップ

\int_{0}^{9} \frac{1}{3} x - 2 d x

総和規則を適用する:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int_{0}^{9} \frac{1}{3} x d x - \int_{0}^{9} 2 d x

\int_{0}^{9} \frac{1}{3} x d x = \frac{27}{2}

\int_{0}^{9} 2 d x = 18

= \frac{27}{2} - 18

簡素化

\frac{27}{2} - 18 : - \frac{9}{2}

= - \frac{9}{2}