What is area x=-2,x=1,y=7x,y=x^2-8 ?

The answer to area x=-2,x=1,y=7x,y=x^2-8 is 121/6

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area x=-2,x=1,y=7x,y=x^2-8

area

x = - 2, x = 1, y = 7 x, y = x^{2} - 8

\frac{121}{6}

Decimal Notation

20.16666 \dots

Solution steps

Apply the area formula:

\int_{- 2}^{1} 7 x - (x^{2} - 8) d x

Solve

\int_{- 2}^{1} 7 x - (x^{2} - 8) d x : \frac{121}{6}

The area is:

= \frac{121}{6}

\frac{d y}{d x}, 6 x^{2} + 3 x y + 2 y^{2} + 17 y - 6 = 0

y^{^{''}} - 7 y^{^{'}} + 12 y = 0

2 x + 1

y^{^{''}} - 3 y^{^{'}} + 18 y = 0

\int (x - 2) (x - 3)^{6} d x

What is area x=-2,x=1,y=7x,y=x^2-8 ?
The answer to area x=-2,x=1,y=7x,y=x^2-8 is 121/6