integral from 0 to 3 of x^2-4

Lösung

\int_{0}^{3} x^{2} - 4 d x

- 3

Schritte zur Lösung

\int_{0}^{3} x^{2} - 4 d x

Wende die Summenregel an:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int_{0}^{3} x^{2} d x - \int_{0}^{3} 4 d x

\int_{0}^{3} x^{2} d x = 9

\int_{0}^{3} 4 d x = 12

= 9 - 12

Vereinfache

= - 3

f (t) = 3 cos (2 t)

n = 0 \sum \infty 3^{- n}

x \to - 4 - lim (\frac{- 5 x}{x + 4})

\frac{d y}{d x} + \frac{1}{x} y = x^{2} y^{3}

\frac{\partial}{\partial x} (\frac{1}{4 - 3 x})