(\partial)/(\partial u)(2ucos(v))

解答

\frac{\partial}{\partial u} (2 u cos (v))

2 cos (v)

求解步骤

\frac{\partial}{\partial u} (2 u cos (v))

将

v

视为常数

将常数提出:

(a \cdot f)^{'} = a \cdot f^{'}

= 2 cos (v) \frac{\partial}{\partial u} (u)

使用常见微分定则:

\frac{\partial}{\partial u} (u) = 1

= 2 cos (v) \cdot 1

化简

= 2 cos (v)

y^{^{'}} + y - 4 cos (x) = 0

in v erse l a pl a ce \frac{s}{( s + 2 ) ( s + 3 )}

x \to 0 lim (\frac{1 - cos ( x )}{5 x ^{2}})

y^{^{'}} - y = 10 t e^{2 t}

\int \frac{1}{y ^{2} + 1} d y