(sin^2(x))^'

解答

(sin^{2} (x))^{^{'}}

sin (2 x)

求解步骤

(sin^{2} (x))^{'}

使用连锁律:

2 sin (x) (sin (x))^{'}

= 2 sin (x) (sin (x))^{'}

(sin (x))^{'} = cos (x)

= 2 sin (x) cos (x)

使用倍角公式:

2 sin (x) cos (x) = sin (2 x)

= sin (2 x)

\frac{d}{d x} (4 x^{\frac{1}{3}})

a re a 5 x - x^{2}, 0

h \to 0 lim (h)

2 x^{2} y + x^{3} (\frac{d y}{d x}) = 1

d er i v a t i v e f (x) = \frac{ln ( x )}{x}