斜率 y=sqrt(7x+1),(5,6)

解答

斜率

y = 7 x + 1, (5, 6)

\frac{7}{12}

十进制

0.58333 \dots

求解步骤

y = 7 x + 1

要确定函数的斜率，对

7 x + 1

求导

\frac{d}{d x} (7 x + 1) = \frac{7}{2 7 x + 1}

\frac{7}{2 7 x + 1}

确定

x = 5

时的

\frac{7}{2 7 x + 1}

的值:

\frac{7}{12}

\frac{7}{12}

\frac{\partial}{\partial x} (x y e^{x - 2 z})

\frac{\partial}{\partial x} (A + B \cdot cos (x) sin (y))

\frac{d x}{d t} = x^{\frac{2}{3}}

in v erse l a pl a ce \frac{1}{4 s ^{2}}

y^{^{'}} - y = 3 t e^{2 t}, y (0) = 1