What is the solution for ty^'=t^3+7t^3y ?

The solution for ty^'=t^3+7t^3y is y=(e^{(7t^3+c_{1})/3})/(7)-1/7

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ty^'=t^3+7t^3y

t y^{^{'}} = t^{3} + 7 t^{3} y

y = \frac{e ^{\frac{7 t ^{3} + c _{1}}{3}}}{7} - \frac{1}{7}

Solution steps

t y^{'} (t) = t^{3} + 7 t^{3} y

Solve separable ODE:

y = \frac{e ^{\frac{7 t ^{3} + c _{1}}{3}}}{7} - \frac{1}{7}

y = \frac{e ^{\frac{7 t ^{3} + c _{1}}{3}}}{7} - \frac{1}{7}

\frac{d}{d x} (tan (x) + cot (x))

\int \frac{9 + x}{x} d x

y^{^{'}} = - \frac{4 x}{y}

n = 0 \sum \infty \frac{8}{n !}

y^{^{'}} = 1 - y^{2}

What is the solution for ty^'=t^3+7t^3y ?
The solution for ty^'=t^3+7t^3y is y=(e^{(7t^3+c_{1})/3})/(7)-1/7