What is the tangent of y=(x^3-16x)^{10},(4,0) ?

The tangent of y=(x^3-16x)^{10},(4,0) is y=0

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

tangent of y=(x^3-16x)^{10},(4,0)

tangent of

y = (x^{3} - 16 x)^{10}, (4, 0)

y = 0

Solution steps

Find the slope of

y = (x^{3} - 16 x)^{10} : \frac{d y}{d x} = 10 (x^{3} - 16 x)^{9} (3 x^{2} - 16)

Compute the slope of

y = (x^{3} - 16 x)^{10}

(4, 0) : m = 0

Find the line with slope m=

0

and passing through

(4, 0) : y = 0

y = 0

x \to 0 lim (e^{x} - \frac{1}{x})

\int_{0}^{5} e^{- 2 x} d x

f (x) = \frac{2}{x - 3}

(x^{2} - 3 y^{2}) d x + 2 x y d y = 0

x \to π lim (sin (\frac{11}{6} x))

What is the tangent of y=(x^3-16x)^{10},(4,0) ?
The tangent of y=(x^3-16x)^{10},(4,0) is y=0