derivative 1100+13x-0.1x^2+0.0005x^3

解答

导数

1100 + 13 x - 0.1 x^{2} + 0.0005 x^{3}

0.0015 x^{2} - 0.2 x + 13

求解步骤

\frac{d}{d x} (1100 + 13 x - 0.1 x^{2} + 0.0005 x^{3})

使用微分加减法定则:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (1100) + \frac{d}{d x} (13 x) - \frac{d}{d x} (0.1 x^{2}) + \frac{d}{d x} (0.0005 x^{3})

\frac{d}{d x} (1100) = 0

\frac{d}{d x} (13 x) = 13

\frac{d}{d x} (0.1 x^{2}) = 0.2 x

\frac{d}{d x} (0.0005 x^{3}) = 0.0015 x^{2}

= 0 + 13 - 0.2 x + 0.0015 x^{2}

化简

= 0.0015 x^{2} - 0.2 x + 13

\int \frac{- ( 4 x + 10 )}{x ^{3}} d x

a re a x = \frac{( y - 3 ) ^{2}}{5}, y = 13 - x

\int + \frac{13}{( t ^{2} + 1 ) ^{\frac{3}{2}}} d t

x \to 1 lim (\frac{1}{x})

n \to \infty lim (tanh (n))