What is the derivative of 3e^{-3x} ?

The derivative of 3e^{-3x} is -9e^{-3x}

What is the first derivative of 3e^{-3x} ?

The first derivative of 3e^{-3x} is -9e^{-3x}

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\frac{d}{d x} (3 e^{- 3 x})

- 9 e^{- 3 x}

Solution steps

\frac{d}{d x} (3 e^{- 3 x})

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= 3 \frac{d}{d x} (e^{- 3 x})

Apply the chain rule:

e^{- 3 x} \frac{d}{d x} (- 3 x)

= e^{- 3 x} \frac{d}{d x} (- 3 x)

\frac{d}{d x} (- 3 x) = - 3

= 3 e^{- 3 x} (- 3)

Simplify

= - 9 e^{- 3 x}

\frac{d}{d x} (9 k lo g_{e} (\frac{( x + 9 )}{x - 9}))

\frac{5 s + 50.1}{( s + 5 ) ^{2} - 5}

k = 0 \sum \infty \frac{k - 1}{2 ^{k + 1}}

(x, y) \to (1, 2) lim (1 + x + y)

f (x) = x^{3} - 5 + 2 x

What is the derivative of 3e^{-3x} ?
The derivative of 3e^{-3x} is -9e^{-3x}
What is the first derivative of 3e^{-3x} ?
The first derivative of 3e^{-3x} is -9e^{-3x}