What is the limit as x approaches 1 of sin(pi/2 x) ?

The limit as x approaches 1 of sin(pi/2 x) is 1

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limit as x approaches 1 of sin(pi/2 x)

x \to 1 lim (sin (\frac{π}{2} x))

1

Solution steps

x \to 1 lim (sin (\frac{π}{2} x))

Plug in the value

x = 1

= sin (\frac{π}{2} \cdot 1)

Simplify

sin (\frac{π}{2} \cdot 1) : 1

= 1

t an g e n t f (x) = 4 x, at x = 4

\int - \frac{cos ( x )}{sin ( x )} d x

\int cos (πn t) d t

n = 1 \sum \infty (\frac{π}{6})^{n}

y^{^{''}} - y^{^{'}} + \frac{1}{4} y = 7 + e^{\frac{x}{2}}

What is the limit as x approaches 1 of sin(pi/2 x) ?
The limit as x approaches 1 of sin(pi/2 x) is 1