derivative of 3x^4+4x^3-12x^2+20

Lösung

\frac{d}{d x} (3 x^{4} + 4 x^{3} - 12 x^{2} + 20)

12 x^{3} + 12 x^{2} - 24 x

Schritte zur Lösung

\frac{d}{d x} (3 x^{4} + 4 x^{3} - 12 x^{2} + 20)

Wende die Summen-/Differenzregel an:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (3 x^{4}) + \frac{d}{d x} (4 x^{3}) - \frac{d}{d x} (12 x^{2}) + \frac{d}{d x} (20)

\frac{d}{d x} (3 x^{4}) = 12 x^{3}

\frac{d}{d x} (4 x^{3}) = 12 x^{2}

\frac{d}{d x} (12 x^{2}) = 24 x

\frac{d}{d x} (20) = 0

= 12 x^{3} + 12 x^{2} - 24 x + 0

Vereinfache

= 12 x^{3} + 12 x^{2} - 24 x

\int (1 + x) d x

\int_{3}^{2} \frac{x ^{2} - 1}{x - 1} d x

n = 1 \sum \infty (x - 6)^{n}

x \to + 1 - lim (\frac{1}{x ^{2} + 1})

\frac{\partial}{\partial y} (4 x + 2 y + 2)