What is the integral of sin^4(x ?

The integral of sin^4(x is (x^2sin^4(d))/2+C

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integral of sin^4(x

\int sin^{4} (d) x d x

\frac{x ^{2} sin ^{4} ( d )}{2} + C

Solution steps

\int sin^{4} (d) x d x

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= sin^{4} (d) \cdot \int x d x

Apply the Power Rule

: \frac{x ^{2}}{2}

= sin^{4} (d) \frac{x ^{2}}{2}

Multiply fractions:

a \cdot \frac{b}{c} = \frac{a \cdot b}{c}

= \frac{x ^{2} sin ^{4} ( d )}{2}

Add a constant to the solution

= \frac{x ^{2} sin ^{4} ( d )}{2} + C

x = y^{2} + 6, y = \frac{x}{2} - \frac{3}{2}

t \to 0 lim (cos (t) sin (t))

\int cos^{5} (x) sin^{2} (x) d x

2 y^{3} + x y - y = 250 x^{4}, (1, 5)

\frac{d}{d x} ((1 - cos (x))^{2})