y^'+y=yxe^{x+2}

Lösung

y^{^{'}} + y = y x e^{x + 2}

y = e^{e^{2} (e^{x} x - e^{x}) - x + c_{1}}

Schritte zur Lösung

y^{'} (x) + y = y x e^{x + 2}

Solve separable ODE:

y = e^{e^{2} (e^{x} x - e^{x}) - x + c_{1}}

y = e^{e^{2} (e^{x} x - e^{x}) - x + c_{1}}

\int \frac{x}{3 x + 4} d x

x \to 3 lim (\frac{1}{( x - 3 ) ^{8}})

x \to - 3 lim (\frac{x ^{2} - 9}{3 + x})

\frac{d}{d x} (\frac{2}{3 x ^{\frac{1}{3}}})

\int_{3}^{5} \frac{x}{x ^{2} - 3} d x