integral from 0 to 2 of (4x-x^3)

Lösung

\int_{0}^{2} (4 x - x^{3}) d x

4

Schritte zur Lösung

\int_{0}^{2} 4 x - x^{3} d x

Wende die Summenregel an:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int_{0}^{2} 4 x d x - \int_{0}^{2} x^{3} d x

\int_{0}^{2} 4 x d x = 8

\int_{0}^{2} x^{3} d x = 4

= 8 - 4

Vereinfache

= 4

in v erse l a pl a ce \frac{( 4 s - 3 )}{( s ^{2} + 8 s + 24 )}

a re a x + 2 y = 7, x + 8 = y^{2}

\int 14 x^{6} y^{- 4} - 12 x^{5} y^{- 3} d x

x \to 3 lim (12 - x - 3)

x \to \infty lim ((1 + (\frac{2}{x}))^{(\frac{x}{4})})