What is the tangent of ysin(8x)=xcos(2y),(pi/2 , pi/4) ?

The tangent of ysin(8x)=xcos(2y),(pi/2 , pi/4) is y=-2x+pi/4+pi

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tangent of ysin(8x)=xcos(2y),(pi/2 , pi/4)

tangent of

y sin (8 x) = x cos (2 y), (\frac{π}{2}, \frac{π}{4})

y = - 2 x + \frac{π}{4} + π

Solution steps

Find the slope of

y sin (8 x) = x cos (2 y) : \frac{d y}{d x} = \frac{cos ( 2 y ) - 8 y cos ( 8 x )}{sin ( 8 x ) + 2 x sin ( 2 y )}

Compute the slope of

y sin (8 x) = x cos (2 y)

(\frac{π}{2}, \frac{π}{4}) : m = - 2

Find the line with slope m=

- 2

and passing through

(\frac{π}{2}, \frac{π}{4}) : y = - 2 x + \frac{π}{4} + π

y = - 2 x + \frac{π}{4} + π

\frac{d}{d x} (5 sec (2 x))

\int y ln (y) d y

\frac{d y}{d x}, e^{2 x} sin (3 x) - e^{- 2 x} sin (2 y) = 13 x y^{2}

cos (x) + sin (x)

\int_{0}^{k} \frac{1}{x ^{2} + 1} d x

What is the tangent of ysin(8x)=xcos(2y),(pi/2 , pi/4) ?
The tangent of ysin(8x)=xcos(2y),(pi/2 , pi/4) is y=-2x+pi/4+pi