derivative 3/(2x+4)+9x^2

Lösung

ableitung von

\frac{3}{2 x + 4} + 9 x^{2}

- \frac{3}{2 ( x + 2 ) ^{2}} + 18 x

Schritte zur Lösung

\frac{d}{d x} (\frac{3}{2 x + 4} + 9 x^{2})

Wende die Summen-/Differenzregel an:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (\frac{3}{2 x + 4}) + \frac{d}{d x} (9 x^{2})

\frac{d}{d x} (\frac{3}{2 x + 4}) = - \frac{3}{2 ( x + 2 ) ^{2}}

\frac{d}{d x} (9 x^{2}) = 18 x

= - \frac{3}{2 ( x + 2 ) ^{2}} + 18 x

x \to 0 + lim ((1 - 2 x)^{\frac{3}{x}})

\int \frac{x ( x + 1 )}{4 x ^{4}} d x

\frac{\partial}{\partial x} (y ln (x + y))

\int 16 e^{- 16 x} d x

\frac{\partial}{\partial x} (e^{\frac{x ^{2}}{y ^{3}}})