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Frequently Asked Questions (FAQ)
What is the solution for y^{''}-8y^'+16y=t^{-3}e^{4t} ?
- The solution for y^{''}-8y^'+16y=t^{-3}e^{4t} is y=c_{1}e^{4t}+c_{2}te^{4t}+(e^{4t})/(2t)