What is area y=2,y=sin(x),x=0,x=pi ?

The answer to area y=2,y=sin(x),x=0,x=pi is 2pi-2

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area y=2,y=sin(x),x=0,x=pi

area

y = 2, y = sin (x), x = 0, x = π

2 π - 2

Decimal Notation

4.28318 \dots

Solution steps

Apply the area formula:

\int_{0}^{π} ∣ 2 - sin (x) ∣ d x

Solve

\int_{0}^{π} ∣ 2 - sin (x) ∣ d x : 2 π - 2

The area is:

= 2 π - 2

\frac{5}{( s ) ( s ^{2} + s + 2 )}

x = 1 \sum \infty \frac{( ( 2 x ) ^{x} )}{x ^{2 x}}

\int \frac{2 x}{π} d x

t^{6}

y = y^{^{'}} + 2

What is area y=2,y=sin(x),x=0,x=pi ?
The answer to area y=2,y=sin(x),x=0,x=pi is 2pi-2