What is the solution for y^{''}+16y^'=0,y(0)=2,y(0)=-2 ?

The solution for y^{''}+16y^'=0,y(0)=2,y(0)=-2 is y=2-c_{2}+c_{2}e^{-16t}

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y^{''}+16y^'=0,y(0)=2,y(0)=-2

y^{^{''}} + 16 y^{^{'}} = 0, y (0) = 2, y (0) = - 2

y = 2 - c_{2} + c_{2} e^{- 16 t}

Solution steps

y^{''} (t) + 16 y^{'} (t) = 0

Solve linear ODE:

y = 2 - c_{2} + c_{2} e^{- 16 t}

y = 2 - c_{2} + c_{2} e^{- 16 t}

x \to 1 lim (3 x + 7)

y = 4 x + 84, (4, 10)

\frac{d}{d x} (3 x^{2} (2 x + 5)^{3})

\int \frac{cos ( \frac{π}{x ^{9}} )}{x ^{10}} d x

\int_{1}^{2} t t - 1 d t

What is the solution for y^{''}+16y^'=0,y(0)=2,y(0)=-2 ?
The solution for y^{''}+16y^'=0,y(0)=2,y(0)=-2 is y=2-c_{2}+c_{2}e^{-16t}