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Popular >

x*y^'+y^2=0

Solution

x \cdot y^{^{'}} + y^{2} = 0

Solution

y = - \frac{1}{- ln ( x ) + c _{1}}

Solution steps

x \cdot y^{'} (x) + y^{2} = 0

Solve separable ODE:

y = - \frac{1}{- ln ( x ) + c _{1}}

y = - \frac{1}{- ln ( x ) + c _{1}}

Popular Examples

integral of sqrt(5+4x-x^2)

\int 5 + 4 x - x^{2} d x

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\int \frac{6}{x ^{6}} d x

derivative of 1-4/(x^2)

\frac{d}{d x} (1 - \frac{4}{x ^{2}})

sum from n=1 to infinity of 2^nx^{n-1}

n = 1 \sum \infty 2^{n} x^{n - 1}

(\frac{4}{3} π r^{3})^{^{'}}

Frequently Asked Questions (FAQ)

What is the solution for x*y^'+y^2=0 ?
The solution for x*y^'+y^2=0 is y=-1/(-ln(x)+c_{1)}