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人気のある微分積分 >

y^{''}+4y=0,y(0)=1,y(1)=0

解

y^{^{''}} + 4 y = 0, y (0) = 1, y (1) = 0

解

y = cos (2 t) - \frac{cos ( 2 ) sin ( 2 t )}{sin ( 2 )}

解答ステップ

y^{''} (t) + 4 y = 0

線形 ODE を解く:

y = cos (2 t) - \frac{cos ( 2 ) sin ( 2 t )}{sin ( 2 )}

y = cos (2 t) - \frac{cos ( 2 ) sin ( 2 t )}{sin ( 2 )}

人気の例

d/(dt)(ae^tcos(2t)+be^tsin(2t))

\frac{d}{d t} (a e^{t} cos (2 t) + b e^{t} sin (2 t))

limit as x approaches 0 of (1+x)^2-1

x \to 0 lim ((1 + x)^{2} - 1)

limit as x approaches 1 of sqrt(6x^2+1)

x \to 1 lim (6 x^{2} + 1)

limit as x approaches 1 of \sqrt[3]{x}-1

x \to 1 lim (3 x - 1)

integral of 1/(4+v^2)

\int \frac{1}{4 + v ^{2}} d v