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Popular >

area 2x,x^2

Solution

area

2 x, x^{2}

Solution

\frac{4}{3}

+1

Solution steps

Apply the area formula:

\int_{0}^{2} 2 x - x^{2} d x

Solve

\int_{0}^{2} 2 x - x^{2} d x : \frac{4}{3}

The area is:

= \frac{4}{3}

Popular Examples

integral of (2x+y+z)/((x+y)(x+z))

\int \frac{2 x + y + z}{( x + y ) ( x + z )} d x

tangent of 8x^2-7x,\at 9 tangent of

8 x^{2} - 7 x, at 9

y^3-(6x+8)+3xy^2y^'=0

y^{3} - (6 x + 8) + 3 x y^{2} y^{^{'}} = 0

4y^{''}+4y^'+1y=0,y(2)=-6,y^'(2)=4

4 y^{^{''}} + 4 y^{^{'}} + 1 y = 0, y (2) = - 6, y^{^{'}} (2) = 4

integral from 3 to 6 of x/(sqrt(x-3))

\int_{3}^{6} \frac{x}{x - 3} d x

Frequently Asked Questions (FAQ)

What is area 2x,x^2 ?
The answer to area 2x,x^2 is 4/3