What is implicit 2x^2+y^2=9 ?

The answer to implicit 2x^2+y^2=9 is (dy}{dx}=-\frac{2x)/y

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implicit 2x^2+y^2=9

implicit derivative

2 x^{2} + y^{2} = 9

\frac{d y}{d x} = - \frac{2 x}{y}

Solution steps

2 x^{2} + y^{2} = 9

Treat

y

y (x)

Differentiate both sides:

4 x + 2 y \frac{d y}{d x} = 0

Isolate

\frac{d y}{d x} : \frac{d y}{d x} = - \frac{2 x}{y}

\frac{d y}{d x} = - \frac{2 x}{y}

a re a e^{x}, e^{- 4 x}, ln (3)

d er i v a t i v e f (x) = 7 e^{x} + x

\int e \cdot t^{2} d t

s im pl i f y x^{- 5} + x^{\frac{1}{2}}

\frac{\partial}{\partial x} (2 e^{x - y})

What is implicit 2x^2+y^2=9 ?
The answer to implicit 2x^2+y^2=9 is (dy}{dx}=-\frac{2x)/y