What is the solution for y^{''}+5y^'=0,y(0)=0 ?

The solution for y^{''}+5y^'=0,y(0)=0 is y=-c_{2}+c_{2}e^{-5t}

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y^{''}+5y^'=0,y(0)=0

y^{^{''}} + 5 y^{^{'}} = 0, y (0) = 0

y = - c_{2} + c_{2} e^{- 5 t}

Solution steps

y^{''} (t) + 5 y^{'} (t) = 0

Solve linear ODE:

y = - c_{2} + c_{2} e^{- 5 t}

y = - c_{2} + c_{2} e^{- 5 t}

2 x + 5 x^{\frac{2}{5}}

\frac{d}{d t} (t + 8)

\frac{d}{d x} (- sin (4 x) 4)

\frac{\partial}{\partial y} (x cos (y) - y e^{x})

\int_{1}^{2} 4 x^{2} ln (x) d x

What is the solution for y^{''}+5y^'=0,y(0)=0 ?
The solution for y^{''}+5y^'=0,y(0)=0 is y=-c_{2}+c_{2}e^{-5t}