What is the derivative of-sin(4x4) ?

The derivative of-sin(4x4) is -16cos(4x)

What is the first derivative of-sin(4x4) ?

The first derivative of-sin(4x4) is -16cos(4x)

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\frac{d}{d x} (- sin (4 x) 4)

- 16 cos (4 x)

Solution steps

\frac{d}{d x} (- sin (4 x) \cdot 4)

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= - 4 \frac{d}{d x} (sin (4 x))

Apply the chain rule:

cos (4 x) \frac{d}{d x} (4 x)

= cos (4 x) \frac{d}{d x} (4 x)

\frac{d}{d x} (4 x) = 4

= - 4 cos (4 x) \cdot 4

Simplify

= - 16 cos (4 x)

\frac{\partial}{\partial y} (x cos (y) - y e^{x})

\int_{1}^{2} 4 x^{2} ln (x) d x

f (x) = \frac{x}{x ^{2} + 4}, at x = 0

\int_{0}^{1} \frac{28}{x ^{2} - 49} d x

6 y^{^{''}} - 6 y^{^{'}} + 15 y = 0

What is the derivative of-sin(4x4) ?
The derivative of-sin(4x4) is -16cos(4x)
What is the first derivative of-sin(4x4) ?
The first derivative of-sin(4x4) is -16cos(4x)