What is the tangent of f(x)=(e^{2x}-4)^2,(0,9) ?

The tangent of f(x)=(e^{2x}-4)^2,(0,9) is y=-12x+9

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tangent of f(x)=(e^{2x}-4)^2,(0,9)

tangent of

f (x) = (e^{2 x} - 4)^{2}, (0, 9)

y = - 12 x + 9

Solution steps

Find the slope of

f (x) = (e^{2 x} - 4)^{2} : \frac{df ( x )}{d x} = 4 e^{2 x} (e^{2 x} - 4)

Compute the slope of

f (x) = (e^{2 x} - 4)^{2}

(0, 9) : m = - 12

Find the line with slope m=

- 12

and passing through

(0, 9) : y = - 12 x + 9

y = - 12 x + 9

x \to 0 lim (\frac{2 cos ( x ) - 2}{x})

x \to \infty lim (7^{x})

\int \frac{cos ^{2} ( x )}{x} d x

x \to \infty lim (3^{x} - 1)

\frac{d}{d x} ((- x^{2} + 6 x - 4)^{5})

What is the tangent of f(x)=(e^{2x}-4)^2,(0,9) ?
The tangent of f(x)=(e^{2x}-4)^2,(0,9) is y=-12x+9