What is the limit as x approaches 1 of 5/(x^3-1) ?

The limit as x approaches 1 of 5/(x^3-1) is diverges

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limit as x approaches 1 of 5/(x^3-1)

x \to 1 lim (\frac{5}{x ^{3} - 1})

diverges

Solution steps

x \to 1 lim (\frac{5}{x ^{3} - 1})

x \to a - lim f (x) \neq = x \to a + lim f (x)

then the limit does not exist

x \to 1 + lim (\frac{5}{x ^{3} - 1}) = \infty

x \to 1 - lim (\frac{5}{x ^{3} - 1}) = - \infty

= diverges

n = 0 \sum \infty 4 n^{2}

\frac{d}{d x} (- 6 cos (\frac{x}{2}) + 5 x)

\int 2 y sin (x) + 2 d y

f (x) = x^{x}

x \to 0 lim (\frac{( 1 - x ) ^{n} - 1}{x})

What is the limit as x approaches 1 of 5/(x^3-1) ?
The limit as x approaches 1 of 5/(x^3-1) is diverges