What is the derivative of (3x^2+7^3) ?

The derivative of (3x^2+7^3) is 18x(3x^2+7)^2

What is the first derivative of (3x^2+7^3) ?

The first derivative of (3x^2+7^3) is 18x(3x^2+7)^2

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\frac{d}{d x} ((3 x^{2} + 7)^{3})

18 x (3 x^{2} + 7)^{2}

Solution steps

\frac{d}{d x} ((3 x^{2} + 7)^{3})

Apply the chain rule:

3 (3 x^{2} + 7)^{2} \frac{d}{d x} (3 x^{2} + 7)

= 3 (3 x^{2} + 7)^{2} \frac{d}{d x} (3 x^{2} + 7)

\frac{d}{d x} (3 x^{2} + 7) = 6 x

= 3 (3 x^{2} + 7)^{2} \cdot 6 x

Simplify

= 18 x (3 x^{2} + 7)^{2}

x \to + 2 - lim (x (x - 1))

\int \frac{2 x ^{3}}{( x ^{2} + 1 ) ^{2}} d x

\frac{d}{d x} (\frac{( x + 1 )}{( x ^{3} + x - 2 )})

\frac{2 x}{x ^{2} + 1}

x^{3}, at x = 0

What is the derivative of (3x^2+7^3) ?
The derivative of (3x^2+7^3) is 18x(3x^2+7)^2
What is the first derivative of (3x^2+7^3) ?
The first derivative of (3x^2+7^3) is 18x(3x^2+7)^2