What is (\partial)/(\partial y)(e^{-x}+y^2) ?

The answer to (\partial)/(\partial y)(e^{-x}+y^2) is 2y

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(\partial)/(\partial y)(e^{-x}+y^2)

\frac{\partial}{\partial y} (e^{- x} + y^{2})

2 y

Solution steps

\frac{\partial}{\partial y} (e^{- x} + y^{2})

Treat

x

as a constant

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{\partial}{\partial y} (e^{- x}) + \frac{\partial}{\partial y} (y^{2})

\frac{\partial}{\partial y} (e^{- x}) = 0

\frac{\partial}{\partial y} (y^{2}) = 2 y

= 0 + 2 y

Simplify

= 2 y

\frac{\partial}{\partial x} (9 x sin (5 x^{2} y))

x \to \infty lim (8 - e^{x})

\int \frac{3 ( x - 3 ) ^{2}}{16} d x

\int (x + 7) d x

x \to 2 + lim (\frac{4}{( x - 2 ) ^{3}})

What is (\partial)/(\partial y)(e^{-x}+y^2) ?
The answer to (\partial)/(\partial y)(e^{-x}+y^2) is 2y