What is the derivative of sqrt(x)+1/(\sqrt[3]{x}) ?

The derivative of sqrt(x)+1/(\sqrt[3]{x}) is 1/(2sqrt(x))-1/(3x^{4/3)}

What is the first derivative of sqrt(x)+1/(\sqrt[3]{x}) ?

The first derivative of sqrt(x)+1/(\sqrt[3]{x}) is 1/(2sqrt(x))-1/(3x^{4/3)}

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Popular >

\frac{1}{2 x} - \frac{1}{3 x ^{\frac{4}{3}}}

Solution steps

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

\frac{d}{d x} (x) = \frac{1}{2 x}

= \frac{1}{2 x} - \frac{1}{3 x ^{\frac{4}{3}}}

x \to - \infty lim (2^{x})

n \to \infty lim (\frac{( - 1 ) ^{n + 1}}{( n + 3 ) \cdot n !})

\int x^{3} x^{2} - 8 d x

\int e^{3 x} sin (2 x) d x

n = 3 \sum \infty e^{3 - 6 n}

What is the derivative of sqrt(x)+1/(\sqrt[3]{x}) ?
The derivative of sqrt(x)+1/(\sqrt[3]{x}) is 1/(2sqrt(x))-1/(3x^{4/3)}
What is the first derivative of sqrt(x)+1/(\sqrt[3]{x}) ?
The first derivative of sqrt(x)+1/(\sqrt[3]{x}) is 1/(2sqrt(x))-1/(3x^{4/3)}